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  1. #include <stdio.h>
  2. //正の奇数nを引数とし，以下の正の奇数の和を求める関数
  3. int rec(int n){
  4.     if (n <= 2){
  5.         return n;
  6.     }
  7.     else{
  8.         return rec(n-2)+n;
  9.     }
  10. }
  11. int main(void) {
  12.     int n = 10;
  13.     if(n%2==0){
  14.     printf("%d以下の正の偶数の和は%d\n", n, rec(n));
  15.     }
  16.     else{
  17.     	 printf("%d以下の正の奇数の和は%d\n", n, rec(n));
  18.     }
  19. 	return 0;
  20. }
Success #stdin #stdout 0s 5276KB
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10以下の正の偶数の和は30
https://ideone.com/W0xKvs
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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