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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4. 	int ave=0;
  5. 	int count=0;
  6. 	for(;s[count]!='\0';count++){
  7. 		;
  8. 	}
  9. 	if(count%2==1){
  10. 		ave=(count/2)+1;
  11. 	}
  12. 	else{
  13. 		ave=count/2;
  14. 	}
  15. 	for(int i=0;s[i]==s[count-i-1];i++){
  16. 		if(i==ave){
  17. 			return 1;
  18. 		}
  19. 	}
  20. 	return 0;
  21. }
  22.  
  23.  
  24. int main(){
  25.     char s[100];
  26.     scanf("%s",s);
  27.     printf("%s -> %d\n",s,isPalindrome(s));
  28.     return 0;
  29. }
  30.  
Success #stdin #stdout 0s 5316KB
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https://ideone.com/kY2SRV
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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